This program shows how to check for in the given list of numbers
whether each number is palindrome or not
*/
public class JavaPalindromeNumberExample {
public static void main(String[] args) {
//array of numbers to be checked
int numbers[] = new int[]{121, 13, 34, 11, 22, 54};
//iterate through the numbers
for (int i = 0; i < numbers.length; i++) {
int number = numbers[i];
int reversedNumber = 0;
int temp = 0;
/*
* If the number is equal to it's reversed number, then
* the given number is a palindrome number.
*
* For ex,121 is a palindrome number while 12 is not.
*/
//reverse the number
while (number > 0) {
temp = number % 10;
number = number / 10;
reversedNumber = reversedNumber * 10 + temp;
}
if (numbers[i] == reversedNumber) {
System.out.println(numbers[i] + " is a palindrome");
} else {
System.out.println(numbers[i] + " not a palindrome ");
}
}
}
}
/*
Output of Java Palindrome Number Example would be
121 is a palindrome number
13 is not a palindrome number
34 is not a palindrome number
11 is a palindrome number
22 is a palindrome number
54 is not a palindrome number
*/
